derivative f(t)=t^4-20t^3+112t^2

Lösung

ableitung von

f (t) = t^{4} - 20 t^{3} + 112 t^{2}

4 t^{3} - 60 t^{2} + 224 t

Schritte zur Lösung

\frac{d}{d t} (t^{4} - 20 t^{3} + 112 t^{2})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{4}) - \frac{d}{d t} (20 t^{3}) + \frac{d}{d t} (112 t^{2})

\frac{d}{d t} (t^{4}) = 4 t^{3}

\frac{d}{d t} (20 t^{3}) = 60 t^{2}

\frac{d}{d t} (112 t^{2}) = 224 t

= 4 t^{3} - 60 t^{2} + 224 t

t an g e n t f (x) = arccos (x) + x, at x = 0

t \frac{d y}{d t} + 18 y = \frac{1}{t}

t an g e n t f (x) = \frac{2 x - 1}{x + 3}, at x = 3

\int - sin (t) d t

\frac{\partial ^{2}}{\partial x \partial y} (ln (3 x^{2} - y^{3} - 3))