What is the solution for (19xy^2-15y)+(19x^2y-15x)y^'=0 ?

The solution for (19xy^2-15y)+(19x^2y-15x)y^'=0 is y=(c_{1})/x

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(19xy^2-15y)+(19x^2y-15x)y^'=0

(19 x y^{2} - 15 y) + (19 x^{2} y - 15 x) y^{^{'}} = 0

y = \frac{c _{1}}{x}

Solution steps

(19 x y^{2} - 15 y) + (19 x^{2} y - 15 x) y^{'} (x) = 0

Solve linear ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

\int \frac{sec ( x ) + cos ( x )}{7 cos ( x )} d x

\frac{d}{d x} (x^{4} \frac{1}{8} + \frac{1}{4 x ^{2}})

\frac{d}{d x} ((6 x + 1)^{2})

y^{^{''}} - 25 y = 0

y^{^{'}} + 27 y = \frac{1}{x ^{2}}

What is the solution for (19xy^2-15y)+(19x^2y-15x)y^'=0 ?
The solution for (19xy^2-15y)+(19x^2y-15x)y^'=0 is y=(c_{1})/x