What is the derivative of-3/4 e^{-x/4} ?

The derivative of-3/4 e^{-x/4} is 3/16 e^{-x/4}

What is the first derivative of-3/4 e^{-x/4} ?

The first derivative of-3/4 e^{-x/4} is 3/16 e^{-x/4}

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\frac{d}{d x} (- \frac{3}{4} e^{- \frac{x}{4}})

\frac{3}{16} e^{- \frac{x}{4}}

Solution steps

\frac{d}{d x} (- \frac{3}{4} e^{- \frac{x}{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{3}{4} \frac{d}{d x} (e^{- \frac{x}{4}})

Apply the chain rule:

e^{- \frac{x}{4}} \frac{d}{d x} (- \frac{x}{4})

= e^{- \frac{x}{4}} \frac{d}{d x} (- \frac{x}{4})

\frac{d}{d x} (- \frac{x}{4}) = - \frac{1}{4}

= - \frac{3}{4} e^{- \frac{x}{4}} (- \frac{1}{4})

Simplify

- \frac{3}{4} e^{- \frac{x}{4}} (- \frac{1}{4}) : \frac{3}{16} e^{- \frac{x}{4}}

= \frac{3}{16} e^{- \frac{x}{4}}

\frac{\partial}{\partial x} (- e^{- x} cos (y))

\int \frac{4 x ^{5}}{9 - 16 x ^{6}} d x

\frac{d}{d x} ((x^{x} + 1)^{2})

f (x) = x^{2} + 2 x - 1, (1, 2)

\int 10 (x + 1) (x^{2} + 2 x + 3)^{4} d x

What is the derivative of-3/4 e^{-x/4} ?
The derivative of-3/4 e^{-x/4} is 3/16 e^{-x/4}
What is the first derivative of-3/4 e^{-x/4} ?
The first derivative of-3/4 e^{-x/4} is 3/16 e^{-x/4}