What is the derivative of (x^x+1^2) ?

The derivative of (x^x+1^2) is 2(x^x+1)x^x(ln(x)+1)

What is the first derivative of (x^x+1^2) ?

The first derivative of (x^x+1^2) is 2(x^x+1)x^x(ln(x)+1)

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\frac{d}{d x} ((x^{x} + 1)^{2})

2 (x^{x} + 1) x^{x} (ln (x) + 1)

Solution steps

\frac{d}{d x} ((x^{x} + 1)^{2})

Apply the chain rule:

2 (x^{x} + 1) \frac{d}{d x} (x^{x} + 1)

= 2 (x^{x} + 1) \frac{d}{d x} (x^{x} + 1)

\frac{d}{d x} (x^{x} + 1) = x^{x} (ln (x) + 1)

= 2 (x^{x} + 1) x^{x} (ln (x) + 1)

f (x) = x^{2} + 2 x - 1, (1, 2)

\int 10 (x + 1) (x^{2} + 2 x + 3)^{4} d x

\frac{d}{d x} (a r (x) cos (\frac{x + 1}{3}))

\frac{d}{d x} (18 x - \frac{2}{3} x^{3})

x \to 1 lim (e^{x} - e)

What is the derivative of (x^x+1^2) ?
The derivative of (x^x+1^2) is 2(x^x+1)x^x(ln(x)+1)
What is the first derivative of (x^x+1^2) ?
The first derivative of (x^x+1^2) is 2(x^x+1)x^x(ln(x)+1)