What is the derivative of Ansqrt(n-b) ?

The derivative of Ansqrt(n-b) is -(An)/(2sqrt(n-b))

What is the first derivative of Ansqrt(n-b) ?

The first derivative of Ansqrt(n-b) is -(An)/(2sqrt(n-b))

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derivative of

A n n - b

- \frac{A n}{2 n - b}

Solution steps

\frac{d}{d b} (A n n - b)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= A n \frac{d}{d b} (n - b)

Apply the chain rule:

\frac{1}{2 n - b} \frac{d}{d b} (n - b)

= \frac{1}{2 n - b} \frac{d}{d b} (n - b)

\frac{d}{d b} (n - b) = - 1

= A n \frac{1}{2 n - b} (- 1)

Simplify

A n \frac{1}{2 n - b} (- 1) : - \frac{A n}{2 n - b}

= - \frac{A n}{2 n - b}

\int_{0}^{1} x^{2} cos (x^{3}) d x

\frac{d}{d x} (6 x^{7} - 2 x^{5} + 2)

n = 0 \sum \infty n e^{- n}

- 1 cos (t)

What is the derivative of Ansqrt(n-b) ?
The derivative of Ansqrt(n-b) is -(An)/(2sqrt(n-b))
What is the first derivative of Ansqrt(n-b) ?
The first derivative of Ansqrt(n-b) is -(An)/(2sqrt(n-b))