What is the derivative of-1cos(t) ?

The derivative of-1cos(t) is sin(t)

What is the first derivative of-1cos(t) ?

The first derivative of-1cos(t) is sin(t)

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derivative of

- 1 cos (t)

sin (t)

Solution steps

\frac{d}{d t} (- 1 \cdot cos (t))

Simplify

- 1 \cdot cos (t) : - cos (t)

= \frac{d}{d t} (- cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d t} (cos (t))

Apply the common derivative:

\frac{d}{d t} (cos (t)) = - sin (t)

= - (- sin (t))

Simplify

= sin (t)

\int_{0}^{1} x (x^{2} + 1) d x

\int - t t - 1 d t

\int (6 e^{u} - u^{3} (u + 1)) d u

\frac{\partial}{\partial x} (\frac{x}{x ^{2} + 1})

\frac{d}{d x} (\frac{3 x + 2}{x - 3})

What is the derivative of-1cos(t) ?
The derivative of-1cos(t) is sin(t)
What is the first derivative of-1cos(t) ?
The first derivative of-1cos(t) is sin(t)