{
"query": {
"display": "$$\\sum_{n=0}^{\\infty\\:}ne^{-n}$$",
"symbolab_question": "BIG_OPERATOR#\\sum _{n=0}^{\\infty }ne^{-n}"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Series",
"subTopic": "Convergence",
"default": "\\mathrm{converges}"
},
"steps": {
"type": "interim",
"title": "Check convergence of $$\\sum_{n=0}^{\\infty\\:}ne^{-n}:{\\quad}$$converges",
"input": "\\sum_{n=0}^{\\infty\\:}ne^{-n}",
"steps": [
{
"type": "interim",
"title": "Apply Series Ratio Test:$${\\quad}$$converges",
"input": "\\sum_{n=0}^{\\infty\\:}ne^{-n}",
"steps": [
{
"type": "definition",
"title": "Series Ratio Test:",
"text": "If there exists an $$N$$ so that for all $$n\\ge{N},\\:{\\quad}a_n\\neq{0}$$ and $$\\lim_{n\\to\\infty}|\\frac{a_{n+1}}{a_{n}}|=L:$$<br/>$${\\quad}$$If $$L<1$$, then $$\\sum{a_n}$$ converges<br/>$${\\quad}$$If $$L>1$$, then $$\\sum{a_n}$$ diverges<br/>$${\\quad}$$If $$L=1$$, then the test is inconclusive"
},
{
"type": "step",
"primary": "$$\\left|\\frac{a_{n+1}}{a_n}\\right|=\\left|\\frac{\\left(n+1\\right)e^{-\\left(n+1\\right)}}{ne^{-n}}\\right|$$"
},
{
"type": "interim",
"title": "Simplify $$\\left|\\frac{\\left(n+1\\right)e^{-\\left(n+1\\right)}}{ne^{-n}}\\right|:{\\quad}\\frac{\\left|n+1\\right|}{e\\left|n\\right|}$$",
"steps": [
{
"type": "step",
"result": "=\\left|\\frac{\\left(n+1\\right)e^{-\\left(n+1\\right)}}{ne^{-n}}\\right|"
},
{
"type": "step",
"primary": "Apply exponent rule: $$\\frac{x^{a}}{x^{b}}=\\frac{1}{x^{b-a}}$$",
"secondary": [
"$$\\frac{e^{-\\left(n+1\\right)}}{e^{-n}}=\\frac{1}{e^{-n-\\left(-\\left(n+1\\right)\\right)}}$$"
],
"result": "=\\frac{n+1}{ne^{-n-\\left(-\\left(n+1\\right)\\right)}}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Add similar elements: $$-n-\\left(-\\left(n+1\\right)\\right)=1$$",
"result": "=\\left|\\frac{n+1}{en}\\right|"
},
{
"type": "step",
"primary": "Apply absolute rule: $$\\left|\\frac{a}{b}\\right|\\:=\\frac{\\left|a\\right|}{\\left|b\\right|}$$",
"result": "=\\frac{\\left|n+1\\right|}{\\left|en\\right|}"
},
{
"type": "step",
"primary": "Apply absolute rule: $$\\left|a\\:\\cdot\\:b\\right|\\:=\\left|a\\right|\\:\\left|b\\right|$$",
"secondary": [
"$$\\left|en\\right|=\\left|e\\right|\\left|n\\right|$$"
],
"result": "=\\frac{\\left|n+1\\right|}{\\left|e\\right|\\left|n\\right|}"
},
{
"type": "step",
"primary": "Apply absolute rule: $$\\left|a\\right|=a,\\:a\\ge0$$",
"secondary": [
"$$\\left|e\\right|=e$$"
],
"result": "=\\frac{\\left|n+1\\right|}{e\\left|n\\right|}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "interim",
"title": "$$\\lim_{n\\to\\:\\infty\\:}\\left(\\frac{\\left|n+1\\right|}{e\\left|n\\right|}\\right)=\\frac{1}{e}$$",
"input": "\\lim_{n\\to\\:\\infty\\:}\\left(\\frac{\\left|n+1\\right|}{e\\left|n\\right|}\\right)",
"steps": [
{
"type": "step",
"primary": "$$n+1$$ is positive when $$n\\to\\:\\infty\\:$$. Therefore $$\\left|n+1\\right|=n+1$$",
"result": "=\\lim_{n\\to\\:\\infty\\:}\\left(\\frac{n+1}{e\\left|n\\right|}\\right)"
},
{
"type": "step",
"primary": "$$n$$ is positive when $$n\\to\\:\\infty\\:$$. Therefore $$\\left|n\\right|=n$$",
"result": "=\\lim_{n\\to\\:\\infty\\:}\\left(\\frac{n+1}{en}\\right)"
},
{
"type": "step",
"primary": "$$\\lim_{x\\to{a}}[c\\cdot{f\\left(x\\right)}]=c\\cdot\\lim_{x\\to{a}}{f\\left(x\\right)}$$",
"result": "=\\frac{1}{e}\\cdot\\:\\lim_{n\\to\\:\\infty\\:}\\left(\\frac{n+1}{n}\\right)"
},
{
"type": "interim",
"title": "Divide by highest denominator power: $$1+\\frac{1}{n}$$",
"input": "\\frac{n+1}{n}",
"result": "=\\frac{1}{e}\\cdot\\:\\lim_{n\\to\\:\\infty\\:}\\left(1+\\frac{1}{n}\\right)",
"steps": [
{
"type": "step",
"primary": "Divide by $$n$$",
"result": "=\\frac{\\frac{n}{n}+\\frac{1}{n}}{\\frac{n}{n}}"
},
{
"type": "step",
"primary": "Refine",
"result": "=1+\\frac{1}{n}"
}
],
"meta": {
"interimType": "Divide By Highest Denominator Power 1Eq",
"practiceLink": "/practice/limits-practice#area=main&subtopic=Rational%20functions",
"practiceTopic": "Rational Functions Limits"
}
},
{
"type": "step",
"primary": "$$\\lim_{x\\to{a}}[f\\left(x\\right)\\pm{g\\left(x\\right)}]=\\lim_{x\\to{a}}{f\\left(x\\right)}\\pm\\lim_{x\\to{a}}{g\\left(x\\right)}$$<br/>With the exception of indeterminate form",
"result": "=\\frac{1}{e}\\left(\\lim_{n\\to\\:\\infty\\:}\\left(1\\right)+\\lim_{n\\to\\:\\infty\\:}\\left(\\frac{1}{n}\\right)\\right)",
"meta": {
"title": {
"extension": "Indeterminate Forms:<br/>$$\\frac{\\pm\\infty}{\\pm\\infty}$$<br/>$$\\frac{0}{0}$$<br/>$$\\pm\\infty\\cdot0$$<br/>$$0^0$$<br/>$$1^{\\pm\\infty}$$<br/>$$\\infty^{0}$$<br/>$$\\infty-\\infty$$"
}
}
},
{
"type": "interim",
"title": "$$\\lim_{n\\to\\:\\infty\\:}\\left(1\\right)=1$$",
"input": "\\lim_{n\\to\\:\\infty\\:}\\left(1\\right)",
"steps": [
{
"type": "step",
"primary": "$$\\lim_{x\\to{a}}{c}=c$$",
"result": "=1"
}
],
"meta": {
"solvingClass": "Limits",
"interimType": "Limits"
}
},
{
"type": "interim",
"title": "$$\\lim_{n\\to\\:\\infty\\:}\\left(\\frac{1}{n}\\right)=0$$",
"input": "\\lim_{n\\to\\:\\infty\\:}\\left(\\frac{1}{n}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply Infinity Property: $$\\lim_{x\\to\\infty}\\left(\\frac{c}{x^a}\\right)=0$$",
"result": "=0"
}
],
"meta": {
"solvingClass": "Limits",
"interimType": "Limits",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7+jbUbsVfpMbXIJ0UHfO5sfBo3vAig8R1lz2YYpgaM3COyRKA+kVWL4EgNcz8UITyk3WldPTzMRCmfRYnoIUxcFAsqG8mG4+AKrheu2ZGyPikLL/bRq43OIhscddZMC8wf7LqB9CcyvYCWDsGseX09hi2Sg2N1jZXcumfy0+UpgDwaN7wIoPEdZc9mGKYGjNwHT+Ezdx8WMx3O68TWD7RsM2K6cO8RrGfyfucGJ9J7KQ="
}
},
{
"type": "step",
"result": "=\\frac{1}{e}\\left(1+0\\right)"
},
{
"type": "step",
"primary": "Simplify",
"result": "=\\frac{1}{e}",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Limits",
"interimType": "Limits"
}
},
{
"type": "step",
"primary": "$$L<1,\\:$$by the ratio test",
"result": "=\\mathrm{converges}"
}
],
"meta": {
"interimType": "Series Apply Ratio Test 0Eq"
}
},
{
"type": "step",
"result": "=\\mathrm{converges}"
}
],
"meta": {
"solvingClass": "Series",
"practiceLink": "/practice/series-practice#area=main&subtopic=Ratio%20Test",
"practiceTopic": "Series Ratio Test"
}
}
}
Solution
Solution
Solution steps
Apply Series Ratio Test:converges
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Frequently Asked Questions (FAQ)
What is the sum from n=0 to infinity of ne^{-n} ?
The sum from n=0 to infinity of ne^{-n} is converges