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Popular >

4xy^'-20y=x^{-5}

Solution

4 x y^{^{'}} - 20 y = x^{- 5}

Solution

y = - \frac{1}{40 x ^{5}} + c_{1} x^{5}

Solution steps

4 x y^{'} (x) - 20 y = x^{- 5}

Solve linear ODE:

y = - \frac{1}{40 x ^{5}} + c_{1} x^{5}

y = - \frac{1}{40 x ^{5}} + c_{1} x^{5}

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Frequently Asked Questions (FAQ)

What is the solution for 4xy^'-20y=x^{-5} ?
The solution for 4xy^'-20y=x^{-5} is y=-1/(40x^5)+c_{1}x^5