{
"query": {
"display": "$$\\int\\:e^{y}\\left(e^{y}+1\\right)^{-2}dy$$",
"symbolab_question": "BIG_OPERATOR#\\int e^{y}(e^{y}+1)^{-2}dy"
},
"solution": {
"level": "PERFORMED",
"subject": "Calculus",
"topic": "Integrals",
"subTopic": "Indefinite Integrals",
"default": "-\\frac{1}{e^{y}+1}+C",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\int\\:e^{y}\\left(e^{y}+1\\right)^{-2}dy=-\\frac{1}{e^{y}+1}+C$$",
"input": "\\int\\:e^{y}\\left(e^{y}+1\\right)^{-2}dy",
"steps": [
{
"type": "interim",
"title": "Simplify $$e^{y}\\left(e^{y}+1\\right)^{-2}:{\\quad}\\frac{e^{y}}{\\left(e^{y}+1\\right)^{2}}$$",
"input": "e^{y}\\left(e^{y}+1\\right)^{-2}",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$a^{-b}=\\frac{1}{a^b}$$",
"secondary": [
"$$\\left(e^{y}+1\\right)^{-2}=\\frac{1}{\\left(e^{y}+1\\right)^{2}}$$"
],
"result": "=e^{y}\\frac{1}{\\left(e^{y}+1\\right)^{2}}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{1\\cdot\\:e^{y}}{\\left(e^{y}+1\\right)^{2}}"
},
{
"type": "step",
"primary": "Multiply: $$1\\cdot\\:e^{y}=e^{y}$$",
"result": "=\\frac{e^{y}}{\\left(e^{y}+1\\right)^{2}}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"result": "=\\int\\:\\frac{e^{y}}{\\left(e^{y}+1\\right)^{2}}dy"
},
{
"type": "interim",
"title": "Apply u-substitution",
"input": "\\int\\:\\frac{e^{y}}{\\left(e^{y}+1\\right)^{2}}dy",
"steps": [
{
"type": "definition",
"title": "Integral Substitution definition",
"text": "$$\\int\\:f\\left(g\\left(x\\right)\\right)\\cdot\\:g'\\left(x\\right)dx=\\int\\:f\\left(u\\right)du,\\:\\quad\\:u=g\\left(x\\right)$$",
"secondary": [
"Substitute: $$u=e^{y}+1$$"
]
},
{
"type": "interim",
"title": "$$\\frac{du}{dy}=e^{y}$$",
"input": "\\frac{d}{dy}\\left(e^{y}+1\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the Sum/Difference Rule: $$\\left(f{\\pm}g\\right)'=f'{\\pm}g'$$",
"result": "=\\frac{d}{dy}\\left(e^{y}\\right)+\\frac{d}{dy}\\left(1\\right)"
},
{
"type": "interim",
"title": "$$\\frac{d}{dy}\\left(e^{y}\\right)=e^{y}$$",
"input": "\\frac{d}{dy}\\left(e^{y}\\right)",
"steps": [
{
"type": "step",
"primary": "Apply the common derivative: $$\\frac{d}{dy}\\left(e^{y}\\right)=e^{y}$$",
"result": "=e^{y}"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYuXAxmneY4KHTzKqTj/QvQik3hxk9aCfAWodBRxXgUexn8DvPuo3s1Tjjq0ztCM2mj/L0MoYg+CUn6oyL3EO7Yrh1NTqo1IauVC4dJ+9+pNcVrQLAn3CCpdhAcVfmnOKQw=="
}
},
{
"type": "interim",
"title": "$$\\frac{d}{dy}\\left(1\\right)=0$$",
"input": "\\frac{d}{dy}\\left(1\\right)",
"steps": [
{
"type": "step",
"primary": "Derivative of a constant: $$\\frac{d}{dx}\\left({a}\\right)=0$$",
"result": "=0"
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79Kg+idP5vLVrjUll6eMdYjo/Vfk8lzzNRp1PIi2YEfNJ8Vk6wvKjVnTtwWT18bQnz7FeFrf3rcM8IZlDz2c0dm5O2bEw0Ql6ne7k1AUriTvtPdL9kNVzLtZYJUOd2Nd5"
}
},
{
"type": "step",
"result": "=e^{y}+0"
},
{
"type": "step",
"primary": "Simplify",
"result": "=e^{y}",
"meta": {
"solvingClass": "Solver"
}
}
],
"meta": {
"solvingClass": "Derivatives",
"interimType": "Derivatives"
}
},
{
"type": "step",
"primary": "$$\\quad\\Rightarrow\\:du=e^{y}dy$$"
},
{
"type": "step",
"primary": "$$\\quad\\Rightarrow\\:dy=\\frac{1}{e^{y}}du$$"
},
{
"type": "step",
"result": "=\\int\\:\\frac{e^{y}}{u^{2}}\\cdot\\:\\frac{1}{e^{y}}du"
},
{
"type": "interim",
"title": "Simplify $$\\frac{e^{y}}{u^{2}}\\cdot\\:\\frac{1}{e^{y}}:{\\quad}\\frac{1}{u^{2}}$$",
"input": "\\frac{e^{y}}{u^{2}}\\cdot\\:\\frac{1}{e^{y}}",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$\\frac{a}{b}\\cdot\\frac{c}{d}=\\frac{a\\:\\cdot\\:c}{b\\:\\cdot\\:d}$$",
"result": "=\\frac{e^{y}\\cdot\\:1}{u^{2}e^{y}}"
},
{
"type": "step",
"primary": "Cancel the common factor: $$e^{y}$$",
"result": "=\\frac{1}{u^{2}}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"result": "=\\int\\:\\frac{1}{u^{2}}du"
}
],
"meta": {
"interimType": "Integral U Substitution 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7l7+Hp9GxvB/5I+4/5L7s72nDKVkElyTlIIFdkNhULG3cRUGfyvL3vVQNE3zBT75lpN4cZPWgnwFqHQUcV4FHsfBLh5j/jJcd1Frv9s/1xSw0pWMfsJc1e/Z0+a/wFZqiVdawfdGtW4aUXHrK9DlWLU/jhwLaEyoMcSFP2OCr+tbwt9LEn7QCBUukJKctfSJKZQn2SiIEHPukOBxMduK6is14g2py5PWS6zSGkqNBJTQ="
}
},
{
"type": "step",
"result": "=\\int\\:\\frac{1}{u^{2}}du"
},
{
"type": "interim",
"title": "Apply the Power Rule",
"input": "\\int\\:\\frac{1}{u^{2}}du",
"result": "=-\\frac{1}{u}",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$\\frac{1}{a^b}=a^{-b}$$",
"secondary": [
"$$\\frac{1}{u^{2}}=u^{-2}$$"
],
"result": "=\\int\\:u^{-2}du",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Apply the Power Rule: $$\\int{x^{a}}dx=\\frac{x^{a+1}}{a+1},\\:\\quad\\:a\\neq{-1}$$",
"result": "=\\frac{u^{-2+1}}{-2+1}"
},
{
"type": "interim",
"title": "Simplify $$\\frac{u^{-2+1}}{-2+1}:{\\quad}-\\frac{1}{u}$$",
"input": "\\frac{u^{-2+1}}{-2+1}",
"steps": [
{
"type": "step",
"primary": "Add/Subtract the numbers: $$-2+1=-1$$",
"result": "=\\frac{u^{-1}}{-1}"
},
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{a}{-b}=-\\frac{a}{b}$$",
"result": "=-\\frac{u^{-1}}{1}"
},
{
"type": "step",
"primary": "Apply rule $$\\frac{a}{1}=a$$",
"result": "=-u^{-1}"
},
{
"type": "step",
"primary": "Apply exponent rule: $$a^{-1}=\\frac{1}{a}$$",
"result": "=-\\frac{1}{u}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"result": "=-\\frac{1}{u}"
}
],
"meta": {
"interimType": "Power Rule Top 0Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7l7+Hp9GxvB/5I+4/5L7s7/RSr02Agv0MR/qV7Nm+eMMy4+rY5ULRUEksemusM4Yyrrf9ZAnPXwtHEGeHjeiUc8XwLUgD2yVoFe9iCfntTx4OQzbEnsuafNY3nX9QxDlJ1HXTSqqQEjS1gpf6I+JyHQS4M5VpC8qh+oehjmM1qmweKkh+28FiXwy+Vsz8xLQiialcV/dI5TH4fXyp+ncwuA=="
}
},
{
"type": "step",
"primary": "Substitute back $$u=e^{y}+1$$",
"result": "=-\\frac{1}{e^{y}+1}"
},
{
"type": "step",
"primary": "Add a constant to the solution",
"result": "=-\\frac{1}{e^{y}+1}+C",
"meta": {
"title": {
"extension": "If $$\\frac{dF\\left(x\\right)}{dx}=f\\left(x\\right)$$ then $$\\int{f\\left(x\\right)}dx=F\\left(x\\right)+C$$"
}
}
}
],
"meta": {
"solvingClass": "Integrals",
"practiceLink": "/practice/integration-practice#area=main&subtopic=Substitution",
"practiceTopic": "Integral Substitution"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "y",
"plotRequest": "y=-\\frac{1}{e^{y}+1}+C"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
Solution steps
Simplify
Apply u-substitution
Apply the Power Rule
Substitute back
Add a constant to the solution
Graph
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Frequently Asked Questions (FAQ)
What is the integral of e^y(e^y+1)^{-2} ?
The integral of e^y(e^y+1)^{-2} is -1/(e^y+1)+C