What is the derivative of sqrt(3x+1) ?

The derivative of sqrt(3x+1) is 3/(2sqrt(3x+1))

What is the first derivative of sqrt(3x+1) ?

The first derivative of sqrt(3x+1) is 3/(2sqrt(3x+1))

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derivative of

3 x + 1

\frac{3}{2 3 x + 1}

Solution steps

\frac{d}{d x} (3 x + 1)

Apply the chain rule:

\frac{1}{2 3 x + 1} \frac{d}{d x} (3 x + 1)

= \frac{1}{2 3 x + 1} \frac{d}{d x} (3 x + 1)

\frac{d}{d x} (3 x + 1) = 3

= \frac{1}{2 3 x + 1} \cdot 3

Simplify

\frac{1}{2 3 x + 1} \cdot 3 : \frac{3}{2 3 x + 1}

= \frac{3}{2 3 x + 1}

\frac{d}{d x} (6 x^{2} + 5 x^{3} y^{4} - 10 y^{5})

\int tan (3 x) sin (3 x) d x

\int (5 x + 4)^{6} d x

f (x) = (2 x + 1)^{6}

t (\frac{d y}{d t}) = t^{3} + 13 t^{3} y

What is the derivative of sqrt(3x+1) ?
The derivative of sqrt(3x+1) is 3/(2sqrt(3x+1))
What is the first derivative of sqrt(3x+1) ?
The first derivative of sqrt(3x+1) is 3/(2sqrt(3x+1))