What is the solution for t((dy)/(dt))=t^3+13t^3y ?

The solution for t((dy)/(dt))=t^3+13t^3y is y=(e^{(13t^3+c_{1})/3})/(13)-1/13

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t((dy)/(dt))=t^3+13t^3y

t (\frac{d y}{d t}) = t^{3} + 13 t^{3} y

y = \frac{e ^{\frac{13 t ^{3} + c _{1}}{3}}}{13} - \frac{1}{13}

Solution steps

t (\frac{d y}{d t}) = t^{3} + 13 t^{3} y

Solve separable ODE:

y = \frac{e ^{\frac{13 t ^{3} + c _{1}}{3}}}{13} - \frac{1}{13}

y = \frac{e ^{\frac{13 t ^{3} + c _{1}}{3}}}{13} - \frac{1}{13}

\frac{d}{d x} (9 x e^{- x})

\frac{14}{( s + 7 ) ^{2}}

\int cos (z)

(1 + x^{2}) y^{^{''}} - 2 x y^{^{'}} + 2 y = 0

\frac{d ^{3}}{d x ^{3}} (ln (x + 2))

What is the solution for t((dy)/(dt))=t^3+13t^3y ?
The solution for t((dy)/(dt))=t^3+13t^3y is y=(e^{(13t^3+c_{1})/3})/(13)-1/13