What is the derivative of ((x^2+x-17))/((x-4)) ?

The derivative of ((x^2+x-17))/((x-4)) is (x^2-8x+13)/((x-4)^2)

What is the first derivative of ((x^2+x-17))/((x-4)) ?

The first derivative of ((x^2+x-17))/((x-4)) is (x^2-8x+13)/((x-4)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{( x ^{2} + x - 17 )}{( x - 4 )}

\frac{x ^{2} - 8 x + 13}{( x - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} + x - 17}{x - 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} + x - 17 ) ( x - 4 ) - \frac{d}{d x} ( x - 4 ) ( x ^{2} + x - 17 )}{( x - 4 ) ^{2}}

\frac{d}{d x} (x^{2} + x - 17) = 2 x + 1

\frac{d}{d x} (x - 4) = 1

= \frac{( 2 x + 1 ) ( x - 4 ) - 1 \cdot ( x ^{2} + x - 17 )}{( x - 4 ) ^{2}}

Simplify

\frac{( 2 x + 1 ) ( x - 4 ) - 1 \cdot ( x ^{2} + x - 17 )}{( x - 4 ) ^{2}} : \frac{x ^{2} - 8 x + 13}{( x - 4 ) ^{2}}

= \frac{x ^{2} - 8 x + 13}{( x - 4 ) ^{2}}

\int_{2}^{3} 6 x ln (x) d x

\frac{d}{d θ} (cos (θ) + i sin (θ))

x \to 0 lim (7)

\int \frac{5 x ^{5}}{x} d x

\int x^{2} + 6 x + 5 d x

What is the derivative of ((x^2+x-17))/((x-4)) ?
The derivative of ((x^2+x-17))/((x-4)) is (x^2-8x+13)/((x-4)^2)
What is the first derivative of ((x^2+x-17))/((x-4)) ?
The first derivative of ((x^2+x-17))/((x-4)) is (x^2-8x+13)/((x-4)^2)