What is the d/(dθ)(cos(θ)+isin(θ)) ?

The d/(dθ)(cos(θ)+isin(θ)) is -sin(θ)+icos(θ)

What is the first d/(dθ)(cos(θ)+isin(θ)) ?

The first d/(dθ)(cos(θ)+isin(θ)) is -sin(θ)+icos(θ)

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\frac{d}{d θ} (cos (θ) + i sin (θ))

- sin (θ) + i cos (θ)

Solution steps

\frac{d}{d θ} (cos (θ) + i sin (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (cos (θ)) + \frac{d}{d θ} (i sin (θ))

\frac{d}{d θ} (cos (θ)) = - sin (θ)

\frac{d}{d θ} (i sin (θ)) = i cos (θ)

= - sin (θ) + i cos (θ)

x \to 0 lim (7)

\int \frac{5 x ^{5}}{x} d x

\int x^{2} + 6 x + 5 d x

\frac{d y}{d x} = 3 y + x^{2} + 2

\int \frac{- 1}{x - 1} d x

What is the d/(dθ)(cos(θ)+isin(θ)) ?
The d/(dθ)(cos(θ)+isin(θ)) is -sin(θ)+icos(θ)
What is the first d/(dθ)(cos(θ)+isin(θ)) ?
The first d/(dθ)(cos(θ)+isin(θ)) is -sin(θ)+icos(θ)