What is the integral of 2/(x^2)-(x^2)/2 ?

The integral of 2/(x^2)-(x^2)/2 is -2/x-(x^3)/6+C

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integral of 2/(x^2)-(x^2)/2

\int \frac{2}{x ^{2}} - \frac{x ^{2}}{2} d x

- \frac{2}{x} - \frac{x ^{3}}{6} + C

Solution steps

\int \frac{2}{x ^{2}} - \frac{x ^{2}}{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2}{x ^{2}} d x - \int \frac{x ^{2}}{2} d x

\int \frac{2}{x ^{2}} d x = - \frac{2}{x}

\int \frac{x ^{2}}{2} d x = \frac{x ^{3}}{6}

= - \frac{2}{x} - \frac{x ^{3}}{6}

Add a constant to the solution

= - \frac{2}{x} - \frac{x ^{3}}{6} + C

n = 1 \sum \infty n e^{- 7 n}

\frac{d}{d x} (arctan^{t a n (x)} (x))

\int \frac{x}{1 + x ^{3}} d x

\frac{d}{d x} (- 8 x - cos (x))

n = 7 \sum \infty e^{5} - 2 n

What is the integral of 2/(x^2)-(x^2)/2 ?
The integral of 2/(x^2)-(x^2)/2 is -2/x-(x^3)/6+C