What is the derivative of-8x-cos(x) ?

The derivative of-8x-cos(x) is -8+sin(x)

What is the first derivative of-8x-cos(x) ?

The first derivative of-8x-cos(x) is -8+sin(x)

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\frac{d}{d x} (- 8 x - cos (x))

- 8 + sin (x)

Solution steps

\frac{d}{d x} (- 8 x - cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (8 x) - \frac{d}{d x} (cos (x))

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (cos (x)) = - sin (x)

= - 8 - (- sin (x))

Simplify

= - 8 + sin (x)

n = 7 \sum \infty e^{5} - 2 n

\frac{d}{d x} (x^{3} x - 4)

\int cot (z) d z

\frac{π}{4} e^{4 x + 15}

x \to 0 lim (\frac{4}{( 5 + x ) ^{2} - 2})

What is the derivative of-8x-cos(x) ?
The derivative of-8x-cos(x) is -8+sin(x)
What is the first derivative of-8x-cos(x) ?
The first derivative of-8x-cos(x) is -8+sin(x)