What is the sum from n=7 to infinity of e^5-2n ?

The sum from n=7 to infinity of e^5-2n is diverges

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sum from n=7 to infinity of e^5-2n

n = 7 \sum \infty e^{5} - 2 n

diverges

Solution steps

n = 7 \sum \infty e^{5} - 2 n

Apply Series Divergence Test:

diverges

= diverges

\frac{d}{d x} (x^{3} x - 4)

\int cot (z) d z

\frac{π}{4} e^{4 x + 15}

x \to 0 lim (\frac{4}{( 5 + x ) ^{2} - 2})

y = ln (x^{14})

What is the sum from n=7 to infinity of e^5-2n ?
The sum from n=7 to infinity of e^5-2n is diverges