What is the integral from-2 to 3 of \sqrt[3]{x} ?

The integral from-2 to 3 of \sqrt[3]{x} is (9\sqrt[3]{3})/4-3/(2^{2/3)}

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integral from-2 to 3 of \sqrt[3]{x}

Solution steps

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{- 2}^{3}

= [\frac{3}{4} x^{\frac{4}{3}}]_{- 2}^{3}

Compute the boundaries:

\int x^{3} x^{2} - 2 d x

y^{^{'}} + \frac{1}{2} y = x

\int_{0}^{1} 4 x^{2} + 1 d x

\int \frac{6}{3 sin ( x ) - 4 cos ( x )} d x

\int \frac{2}{x ^{2}} - \frac{x ^{2}}{2} d x

What is the integral from-2 to 3 of \sqrt[3]{x} ?
The integral from-2 to 3 of \sqrt[3]{x} is (9\sqrt[3]{3})/4-3/(2^{2/3)}