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Popular >

y^'+1/2 y=x

Solution

y^{^{'}} + \frac{1}{2} y = x

Solution

y = 2 x - 4 + \frac{c _{1}}{e ^{\frac{x}{2}}}

Solution steps

y^{'} (x) + \frac{1}{2} y = x

Solve linear ODE:

y = 2 x - 4 + \frac{c _{1}}{e ^{\frac{x}{2}}}

y = 2 x - 4 + \frac{c _{1}}{e ^{\frac{x}{2}}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+1/2 y=x ?
The solution for y^'+1/2 y=x is y=2x-4+(c_{1})/(e^{x/2)}