What is the derivative of (x^2-1)/(x-1) ?

The derivative of (x^2-1)/(x-1) is 1

What is the first derivative of (x^2-1)/(x-1) ?

The first derivative of (x^2-1)/(x-1) is 1

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derivative of

\frac{x ^{2} - 1}{x - 1}

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 1}{x - 1})

Simplify

\frac{x ^{2} - 1}{x - 1} : x + 1

= \frac{d}{d x} (x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 1 + 0

Simplify

= 1

- \frac{6}{( s - 2 ) ^{2}}

\frac{d}{d x} (e^{x y} + ln (\frac{x}{y}))

\frac{d y}{d x} = 4 + y - 4 x + 2

x \to 0 lim (a x)

\frac{d}{d x} (2 x^{2 x})

What is the derivative of (x^2-1)/(x-1) ?
The derivative of (x^2-1)/(x-1) is 1
What is the first derivative of (x^2-1)/(x-1) ?
The first derivative of (x^2-1)/(x-1) is 1