What is inverse oflaplace-6/((s-2)^2) ?

The answer to inverse oflaplace-6/((s-2)^2) is -e^{2t}*6t

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inverse oflaplace-6/((s-2)^2)

inverse laplace

- \frac{6}{( s - 2 ) ^{2}}

- e^{2 t} \cdot 6 t

Solution steps

L^{- 1} {- \frac{6}{( s - 2 ) ^{2}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= - L^{- 1} {\frac{6}{( s - 2 ) ^{2}}}

L^{- 1} {\frac{6}{( s - 2 ) ^{2}}} : e^{2 t} \cdot 6 t

= - e^{2 t} \cdot 6 t

\frac{d}{d x} (e^{x y} + ln (\frac{x}{y}))

\frac{d y}{d x} = 4 + y - 4 x + 2

x \to 0 lim (a x)

\frac{d}{d x} (2 x^{2 x})

\frac{\partial}{\partial x} (x - y^{4})

What is inverse oflaplace-6/((s-2)^2) ?
The answer to inverse oflaplace-6/((s-2)^2) is -e^{2t}*6t