What is the derivative of 2x^{2x} ?

The derivative of 2x^{2x} is 4x^{2x}(ln(x)+1)

What is the first derivative of 2x^{2x} ?

The first derivative of 2x^{2x} is 4x^{2x}(ln(x)+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (2 x^{2 x})

4 x^{2 x} (ln (x) + 1)

Solution steps

\frac{d}{d x} (2 x^{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{2 x})

Apply exponent rule:

a^{b} = e^{b l n (a)}

x^{2 x} = e^{2 x l n (x)}

= 2 \frac{d}{d x} (e^{2 x l n (x)})

Apply the chain rule:

e^{2 x l n (x)} \frac{d}{d x} (2 x ln (x))

= e^{2 x l n (x)} \frac{d}{d x} (2 x ln (x))

\frac{d}{d x} (2 x ln (x)) = 2 (ln (x) + 1)

= 2 e^{2 x l n (x)} \cdot 2 (ln (x) + 1)

Simplify

2 e^{2 x l n (x)} \cdot 2 (ln (x) + 1) : 4 x^{2 x} (ln (x) + 1)

= 4 x^{2 x} (ln (x) + 1)

\frac{\partial}{\partial x} (x - y^{4})

x \to 0 lim (\frac{tan ( a ) x}{x})

\frac{1}{s ( s + 5 )}

x \to 0 lim (\frac{x ^{3}}{e ^{x} - 1})

\int - x^{2} cos (x) d x

What is the derivative of 2x^{2x} ?
The derivative of 2x^{2x} is 4x^{2x}(ln(x)+1)
What is the first derivative of 2x^{2x} ?
The first derivative of 2x^{2x} is 4x^{2x}(ln(x)+1)