What is the integral from 0 to 11/12 of 24x ?

The integral from 0 to 11/12 of 24x is 121/12

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integral from 0 to 11/12 of 24x

\int_{0}^{\frac{11}{12}} 24 x d x

\frac{121}{12}

Decimal Notation

10.08333 \dots

Solution steps

\int_{0}^{\frac{11}{12}} 24 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 24 \cdot \int_{0}^{\frac{11}{12}} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{\frac{11}{12}}

= 24 [\frac{x ^{2}}{2}]_{0}^{\frac{11}{12}}

Compute the boundaries:

\frac{121}{288}

= 24 \cdot \frac{121}{288}

Simplify

= \frac{121}{12}

\frac{\partial}{\partial x} (x^{\frac{2}{3}} \cdot y^{\frac{1}{2}})

\frac{x ^{2} - 1}{x - 1}

- \frac{6}{( s - 2 ) ^{2}}

\frac{d}{d x} (e^{x y} + ln (\frac{x}{y}))

\frac{d y}{d x} = 4 + y - 4 x + 2

What is the integral from 0 to 11/12 of 24x ?
The integral from 0 to 11/12 of 24x is 121/12