What is the derivative of f(x)=sqrt(8x^{10)+6x^6} ?

The derivative of f(x)=sqrt(8x^{10)+6x^6} is (sqrt(2)x^5(20x^4+9))/(sqrt(x^6)\sqrt{4x^4+3)}

What is the first derivative of f(x)=sqrt(8x^{10)+6x^6} ?

The first derivative of f(x)=sqrt(8x^{10)+6x^6} is (sqrt(2)x^5(20x^4+9))/(sqrt(x^6)\sqrt{4x^4+3)}

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derivative of

f (x) = 8 x^{10} + 6 x^{6}

\frac{2 x ^{5} ( 20 x ^{4} + 9 )}{x ^{6} 4 x ^{4} + 3}

Solution steps

\frac{d}{d x} (8 x^{10} + 6 x^{6})

Apply the chain rule:

\frac{1}{2 8 x ^{10} + 6 x ^{6}} \frac{d}{d x} (8 x^{10} + 6 x^{6})

= \frac{1}{2 8 x ^{10} + 6 x ^{6}} \frac{d}{d x} (8 x^{10} + 6 x^{6})

\frac{d}{d x} (8 x^{10} + 6 x^{6}) = 80 x^{9} + 36 x^{5}

= \frac{1}{2 8 x ^{10} + 6 x ^{6}} (80 x^{9} + 36 x^{5})

Simplify

\frac{1}{2 8 x ^{10} + 6 x ^{6}} (80 x^{9} + 36 x^{5}) : \frac{2 x ^{5} ( 20 x ^{4} + 9 )}{x ^{6} 4 x ^{4} + 3}

= \frac{2 x ^{5} ( 20 x ^{4} + 9 )}{x ^{6} 4 x ^{4} + 3}

\int \frac{1}{x ^{2}} e^{\frac{1}{x}} d x

y^{^{'}} + y = - x^{4}

\frac{\partial}{\partial y} (x + \frac{y}{z})

\int 7 x e^{6 x} d x

y = 2 x^{2} + 1, (3, 19)

What is the derivative of f(x)=sqrt(8x^{10)+6x^6} ?
The derivative of f(x)=sqrt(8x^{10)+6x^6} is (sqrt(2)x^5(20x^4+9))/(sqrt(x^6)\sqrt{4x^4+3)}
What is the first derivative of f(x)=sqrt(8x^{10)+6x^6} ?
The first derivative of f(x)=sqrt(8x^{10)+6x^6} is (sqrt(2)x^5(20x^4+9))/(sqrt(x^6)\sqrt{4x^4+3)}