What is area x=-2,x=1,y=3x,y=x^2-4 ?

The answer to area x=-2,x=1,y=3x,y=x^2-4 is 61/6

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area x=-2,x=1,y=3x,y=x^2-4

area

x = - 2, x = 1, y = 3 x, y = x^{2} - 4

\frac{61}{6}

Decimal Notation

10.16666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{1} 3 x - (x^{2} - 4) d x

Solve

\int_{- 2}^{1} 3 x - (x^{2} - 4) d x : \frac{61}{6}

The area is:

= \frac{61}{6}

y^{^{''}} + y = 5 csc^{2} (t)

f (x) = 8 x^{10} + 6 x^{6}

\int \frac{1}{x ^{2}} e^{\frac{1}{x}} d x

y^{^{'}} + y = - x^{4}

\frac{\partial}{\partial y} (x + \frac{y}{z})

What is area x=-2,x=1,y=3x,y=x^2-4 ?
The answer to area x=-2,x=1,y=3x,y=x^2-4 is 61/6