What is the derivative of 2^x+x ?

The derivative of 2^x+x is 2^xln(2)+1

What is the first derivative of 2^x+x ?

The first derivative of 2^x+x is 2^xln(2)+1

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\frac{d}{d x} (2^{x} + x)

2^{x} ln (2) + 1

Solution steps

\frac{d}{d x} (2^{x} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2^{x}) + \frac{d x}{d x}

\frac{d}{d x} (2^{x}) = 2^{x} ln (2)

\frac{d x}{d x} = 1

= 2^{x} ln (2) + 1

x \to 2 lim (\frac{1}{x ^{2}})

x \to π lim (\frac{x}{3} - \frac{2 π}{3})

\frac{d ^{2} x}{d t ^{2}} + 4 x = t^{2}

((5 - 120 x)^{2} + (150 x)^{2})

\int_{0}^{1} (x + 1) d x

What is the derivative of 2^x+x ?
The derivative of 2^x+x is 2^xln(2)+1
What is the first derivative of 2^x+x ?
The first derivative of 2^x+x is 2^xln(2)+1