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Popular >

integral from 0 to 1 of (x+1)

Solution

\int_{0}^{1} (x + 1) d x

Solution

\frac{3}{2}

+1

Decimal Notation

1.5

Solution steps

\int_{0}^{1} x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x d x + \int_{0}^{1} 1 d x

\int_{0}^{1} x d x = \frac{1}{2}

\int_{0}^{1} 1 d x = 1

= \frac{1}{2} + 1

Simplify

\frac{1}{2} + 1 : \frac{3}{2}

= \frac{3}{2}

Popular Examples

integral of-xcos(x+pi/3)+xcos(x)

\int - x cos (x + \frac{π}{3}) + x cos (x) d x

integral of 1/(y(1-y/m))

\int \frac{1}{y ( 1 - \frac{y}{m} )} d y

integral of 5t^4

\int 5 t^{4} d t

integral of (x^2-12x-1)/((x-1)^2(x^2+1))

\int \frac{x ^{2} - 12 x - 1}{( x - 1 ) ^{2} ( x ^{2} + 1 )} d x

derivative of mx+c

\frac{d}{d x} (m x + c)

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (x+1) ?
The integral from 0 to 1 of (x+1) is 3/2