What is the first derivative of mx+c ?

The first derivative of mx+c is m

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derivative of mx+c

\frac{d}{d x} (m x + c)

m

Solution steps

\frac{d}{d x} (m x + c)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (m x) + \frac{d c}{d x}

\frac{d}{d x} (m x) = m

\frac{d c}{d x} = 0

= m + 0

Simplify

= m

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