What is the solution for (dy)/(dx)=(2x-1)/(y^2) ?

The solution for (dy)/(dx)=(2x-1)/(y^2) is y=\sqrt[3]{3x^2-3x+c_{1}}

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(dy)/(dx)=(2x-1)/(y^2)

\frac{d y}{d x} = \frac{2 x - 1}{y ^{2}}

Solution steps

\frac{d y}{d x} = \frac{2 x - 1}{y ^{2}}

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- \frac{( x ^{2} )}{y ^{2}}

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What is the solution for (dy)/(dx)=(2x-1)/(y^2) ?
The solution for (dy)/(dx)=(2x-1)/(y^2) is y=\sqrt[3]{3x^2-3x+c_{1}}