What is (\partial)/(\partial x)(xy(1-7x-6y)) ?

The answer to (\partial)/(\partial x)(xy(1-7x-6y)) is y(-14x-6y+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(xy(1-7x-6y))

\frac{\partial}{\partial x} (x y (1 - 7 x - 6 y))

y (- 14 x - 6 y + 1)

Solution steps

\frac{\partial}{\partial x} (x y (1 - 7 x - 6 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial x} (x (1 - 7 x - 6 y))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = 1 - 7 x - 6 y

= y (\frac{\partial}{\partial x} (x) (1 - 7 x - 6 y) + \frac{\partial}{\partial x} (1 - 7 x - 6 y) x)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (1 - 7 x - 6 y) = - 7

= y (1 \cdot (1 - 7 x - 6 y) + (- 7) x)

Simplify

y (1 \cdot (1 - 7 x - 6 y) + (- 7) x) : y (- 14 x - 6 y + 1)

= y (- 14 x - 6 y + 1)

- \frac{( x ^{2} )}{y ^{2}}

\int \frac{( 1 + x ) ^{2}}{x ^{2} + 1} d x

\frac{( 8 u ^{2} )}{( u ^{2} + u ) ^{3}}

f (x) = x^{2} + x, at x = - 1

\frac{d}{d x} (\frac{2901}{1 + 4.76 e ^{- 0.3 x}})

What is (\partial)/(\partial x)(xy(1-7x-6y)) ?
The answer to (\partial)/(\partial x)(xy(1-7x-6y)) is y(-14x-6y+1)