What is the derivative of-((x^2))/(y^2) ?

The derivative of-((x^2))/(y^2) is -(2x)/(y^2)

What is the first derivative of-((x^2))/(y^2) ?

The first derivative of-((x^2))/(y^2) is -(2x)/(y^2)

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derivative of

- \frac{( x ^{2} )}{y ^{2}}

- \frac{2 x}{y ^{2}}

Solution steps

\frac{d}{d x} (- \frac{x ^{2}}{y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{y ^{2}} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{y ^{2}} \cdot 2 x^{2 - 1}

Simplify

- \frac{1}{y ^{2}} \cdot 2 x^{2 - 1} : - \frac{2 x}{y ^{2}}

= - \frac{2 x}{y ^{2}}

\int \frac{( 1 + x ) ^{2}}{x ^{2} + 1} d x

\frac{( 8 u ^{2} )}{( u ^{2} + u ) ^{3}}

f (x) = x^{2} + x, at x = - 1

\frac{d}{d x} (\frac{2901}{1 + 4.76 e ^{- 0.3 x}})

\frac{\partial}{\partial y} (sin^{2} (m x + n y))

What is the derivative of-((x^2))/(y^2) ?
The derivative of-((x^2))/(y^2) is -(2x)/(y^2)
What is the first derivative of-((x^2))/(y^2) ?
The first derivative of-((x^2))/(y^2) is -(2x)/(y^2)