What is derivative of f(x)=e^{z/((z-2))} ?

The answer to derivative of f(x)=e^{z/((z-2))} is (dz)/(dx)=0

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derivative of f(x)=e^{z/((z-2))}

derivative of

f (x) = e^{\frac{z}{( z - 2 )}}

\frac{d z}{d x} = 0

Solution steps

f (x) = e^{\frac{z}{z - 2}}

Treat

z

z (x)

Differentiate both sides:

0 = - \frac{2 e ^{\frac{z}{z - 2}} \frac{d z}{d x}}{( z - 2 ) ^{2}}

Isolate

\frac{d z}{d x} : \frac{d z}{d x} = 0

\frac{d z}{d x} = 0

\int \frac{1}{( 3 x + 1 ) ^{4}} d x

\frac{\partial}{\partial x} (4 sin (x^{3} y^{2}))

\frac{( 3 u ^{2} )}{( u ^{2} + u ) ^{3}}

\int_{1}^{2} \frac{3}{x ^{2}} - 1 d x

x \to 0 lim (\frac{x}{x})

What is derivative of f(x)=e^{z/((z-2))} ?
The answer to derivative of f(x)=e^{z/((z-2))} is (dz)/(dx)=0