What is the integral from 1 to 2 of 3/(x^2)-1 ?

The integral from 1 to 2 of 3/(x^2)-1 is 1/2

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integral from 1 to 2 of 3/(x^2)-1

\int_{1}^{2} \frac{3}{x ^{2}} - 1 d x

\frac{1}{2}

Decimal Notation

0.5

Solution steps

\int_{1}^{2} \frac{3}{x ^{2}} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} \frac{3}{x ^{2}} d x - \int_{1}^{2} 1 d x

\int_{1}^{2} \frac{3}{x ^{2}} d x = \frac{3}{2}

\int_{1}^{2} 1 d x = 1

= \frac{3}{2} - 1

Simplify

\frac{3}{2} - 1 : \frac{1}{2}

= \frac{1}{2}

x \to 0 lim (\frac{x}{x})

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What is the integral from 1 to 2 of 3/(x^2)-1 ?
The integral from 1 to 2 of 3/(x^2)-1 is 1/2