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Popular >

y^'-y=2x

Solution

y^{^{'}} - y = 2 x

Solution

y = - 2 (x + 1) + c_{1} e^{x}

Solution steps

y^{'} (x) - y = 2 x

Solve linear ODE:

y = - 2 (x + 1) + c_{1} e^{x}

y = - 2 (x + 1) + c_{1} e^{x}

Popular Examples

(\partial)/(\partial z)(2x^2+3y^2-z^2)

\frac{\partial}{\partial z} (2 x^{2} + 3 y^{2} - z^{2})

derivative of 1/((2x+1)^2)derivative of

\frac{1}{( 2 x + 1 ) ^{2}}

integral of 1/(x^2sqrt(4x^2-25))

\int \frac{1}{x ^{2} 4 x ^{2} - 25} d x

derivative of t^2(5t+2)^3 derivative of

t^{2} (5 t + 2)^{3}

integral of e^{4x-7}

\int e^{4 x - 7} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'-y=2x ?
The solution for y^'-y=2x is y=-2(x+1)+c_{1}e^x