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Popular >

derivative of-4cos(x+sin(x))

Solution

\frac{d}{d x} (- 4 cos (x) + sin (x))

Solution

4 sin (x) + cos (x)

Solution steps

\frac{d}{d x} (- 4 cos (x) + sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (4 cos (x)) + \frac{d}{d x} (sin (x))

\frac{d}{d x} (4 cos (x)) = - 4 sin (x)

\frac{d}{d x} (sin (x)) = cos (x)

= - (- 4 sin (x)) + cos (x)

Simplify

= 4 sin (x) + cos (x)

Popular Examples

tangent of f(x)= x/((4x-3)^8),\at x=1 tangent of

f (x) = \frac{x}{( 4 x - 3 ) ^{8}}, at x = 1

area 8-2x,x^3-7x^2+12x,1,4 area

8 - 2 x, x^{3} - 7 x^{2} + 12 x, 1, 4

integral of (x^4+x+1)/(x^3-x)

\int \frac{x ^{4} + x + 1}{x ^{3} - x} d x

y^{^{'}} - y = 2 x

(\partial)/(\partial z)(2x^2+3y^2-z^2)

\frac{\partial}{\partial z} (2 x^{2} + 3 y^{2} - z^{2})

Frequently Asked Questions (FAQ)

What is the derivative of-4cos(x+sin(x)) ?
The derivative of-4cos(x+sin(x)) is 4sin(x)+cos(x)
What is the first derivative of-4cos(x+sin(x)) ?
The first derivative of-4cos(x+sin(x)) is 4sin(x)+cos(x)