What is area 8-2x,x^3-7x^2+12x,1,4 ?

The answer to area 8-2x,x^3-7x^2+12x,1,4 is 37/12

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area 8-2x,x^3-7x^2+12x,1,4

area

8 - 2 x, x^{3} - 7 x^{2} + 12 x, 1, 4

\frac{37}{12}

Decimal Notation

3.08333 \dots

Solution steps

Apply the area formula:

\int_{1}^{4} 8 - 2 x - (x^{3} - 7 x^{2} + 12 x) d x

Solve

\int_{1}^{4} 8 - 2 x - (x^{3} - 7 x^{2} + 12 x) d x : \frac{37}{12}

The area is:

= \frac{37}{12}

\int \frac{x ^{4} + x + 1}{x ^{3} - x} d x

y^{^{'}} - y = 2 x

\frac{\partial}{\partial z} (2 x^{2} + 3 y^{2} - z^{2})

\frac{1}{( 2 x + 1 ) ^{2}}

\int \frac{1}{x ^{2} 4 x ^{2} - 25} d x

What is area 8-2x,x^3-7x^2+12x,1,4 ?
The answer to area 8-2x,x^3-7x^2+12x,1,4 is 37/12