What is the tangent of f(x)=-3cos(x),\at x=-pi/4 ?

The tangent of f(x)=-3cos(x),\at x=-pi/4 is y=-3/(sqrt(2))x-3/(sqrt(2))-(3pi)/(4sqrt(2))

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tangent of f(x)=-3cos(x),\at x=-pi/4

tangent of

f (x) = - 3 cos (x), at x = - \frac{π}{4}

y = - \frac{3}{2} x - \frac{3}{2} - \frac{3 π}{4 2}

Solution steps

Find the tangent point:

(- \frac{π}{4}, - \frac{3}{2})

Find the slope of

f (x) = - 3 cos (x) : \frac{df ( x )}{d x} = 3 sin (x)

Compute the slope of

f (x) = - 3 cos (x)

x = - \frac{π}{4} : m = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(- \frac{π}{4}, - \frac{3}{2}) : y = - \frac{3}{2} x - \frac{3}{2} - \frac{3 π}{4 2}

y = - \frac{3}{2} x - \frac{3}{2} - \frac{3 π}{4 2}

\frac{d}{d x} ((7 x + 5)^{2})

\int x^{3} x^{2} + 27 d x

\frac{( a + h ) ^{4}}{h}

\frac{d}{d x} ((x^{4} - 7 x)^{2})

y^{^{'}} = y (x y^{3} - 1)

What is the tangent of f(x)=-3cos(x),\at x=-pi/4 ?
The tangent of f(x)=-3cos(x),\at x=-pi/4 is y=-3/(sqrt(2))x-3/(sqrt(2))-(3pi)/(4sqrt(2))