What is the derivative of (x^4-7x^2) ?

The derivative of (x^4-7x^2) is 2(x^4-7x)(4x^3-7)

What is the first derivative of (x^4-7x^2) ?

The first derivative of (x^4-7x^2) is 2(x^4-7x)(4x^3-7)

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\frac{d}{d x} ((x^{4} - 7 x)^{2})

2 (x^{4} - 7 x) (4 x^{3} - 7)

Solution steps

\frac{d}{d x} ((x^{4} - 7 x)^{2})

Apply the chain rule:

2 (x^{4} - 7 x) \frac{d}{d x} (x^{4} - 7 x)

= 2 (x^{4} - 7 x) \frac{d}{d x} (x^{4} - 7 x)

\frac{d}{d x} (x^{4} - 7 x) = 4 x^{3} - 7

= 2 (x^{4} - 7 x) (4 x^{3} - 7)

y^{^{'}} = y (x y^{3} - 1)

f (x) = 2^{80}

x \to 1 lim (1 + \frac{1}{x - 1})

\int 2 cos (2 x) d x

\int \frac{4 x}{50 - x ^{2}} d x

What is the derivative of (x^4-7x^2) ?
The derivative of (x^4-7x^2) is 2(x^4-7x)(4x^3-7)
What is the first derivative of (x^4-7x^2) ?
The first derivative of (x^4-7x^2) is 2(x^4-7x)(4x^3-7)