What is the limit as h approaches 0 of ((3+h)^2-9)/h ?

The limit as h approaches 0 of ((3+h)^2-9)/h is 6

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limit as h approaches 0 of ((3+h)^2-9)/h

h \to 0 lim (\frac{( 3 + h ) ^{2} - 9}{h})

6

Solution steps

h \to 0 lim (\frac{( 3 + h ) ^{2} - 9}{h})

Simplify

\frac{( 3 + h ) ^{2} - 9}{h} : h + 6

= h \to 0 lim (h + 6)

Plug in the value

h = 0

= 0 + 6

Simplify

= 6

(\frac{d y}{d t}) = 2 (y^{2} - y) t

f (x) = \frac{3}{t}

\frac{d}{d x} (2 ln (x) - x)

\frac{d}{d x} (sin^{2} (x))

What is the limit as h approaches 0 of ((3+h)^2-9)/h ?
The limit as h approaches 0 of ((3+h)^2-9)/h is 6