What is the solution for ((dy)/(dt))=2(y^2-y)t ?

The solution for ((dy)/(dt))=2(y^2-y)t is y= 1/(1-e^{t^2+c_{1)}}

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((dy)/(dt))=2(y^2-y)t

(\frac{d y}{d t}) = 2 (y^{2} - y) t

y = \frac{1}{1 - e ^{t^{2} + c_{1}}}

Solution steps

(\frac{d y}{d t}) = 2 (y^{2} - y) t

Solve separable ODE:

y = \frac{1}{1 - e ^{t^{2} + c_{1}}}

y = \frac{1}{1 - e ^{t^{2} + c_{1}}}

f (x) = \frac{3}{t}

\frac{d}{d x} (2 ln (x) - x)

\frac{d}{d x} (sin^{2} (x))

y^{^{''}} - 4 y^{^{'}} + 3 y = e^{- x}

What is the solution for ((dy)/(dt))=2(y^2-y)t ?
The solution for ((dy)/(dt))=2(y^2-y)t is y= 1/(1-e^{t^2+c_{1)}}