What is the derivative of 2ln(x-x) ?

The derivative of 2ln(x-x) is 2/x-1

What is the first derivative of 2ln(x-x) ?

The first derivative of 2ln(x-x) is 2/x-1

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\frac{d}{d x} (2 ln (x) - x)

\frac{2}{x} - 1

Solution steps

\frac{d}{d x} (2 ln (x) - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 ln (x)) - \frac{d x}{d x}

\frac{d}{d x} (2 ln (x)) = \frac{2}{x}

\frac{d x}{d x} = 1

= \frac{2}{x} - 1

\frac{d}{d x} (sin^{2} (x))

y^{^{''}} - 4 y^{^{'}} + 3 y = e^{- x}

(5 x + 1)^{2}

f (x) = - 3 cos (x), at x = - \frac{π}{4}

What is the derivative of 2ln(x-x) ?
The derivative of 2ln(x-x) is 2/x-1
What is the first derivative of 2ln(x-x) ?
The first derivative of 2ln(x-x) is 2/x-1