What is the derivative of x^3-4x+7 ?

The derivative of x^3-4x+7 is 3x^2-4

What is the first derivative of x^3-4x+7 ?

The first derivative of x^3-4x+7 is 3x^2-4

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\frac{d}{d x} (x^{3} - 4 x + 7)

3 x^{2} - 4

Solution steps

\frac{d}{d x} (x^{3} - 4 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (7)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (7) = 0

= 3 x^{2} - 4 + 0

Simplify

= 3 x^{2} - 4

x \to 1 lim (x^{2} + x - 2)

\frac{d}{d x} (x^{2} + y^{2} + z^{2})

x \to 4 lim (16)

\frac{d}{d x} (\frac{2 x - 1}{x + 1})

What is the derivative of x^3-4x+7 ?
The derivative of x^3-4x+7 is 3x^2-4
What is the first derivative of x^3-4x+7 ?
The first derivative of x^3-4x+7 is 3x^2-4