What is the derivative of (2x-1/(x+1)) ?

The derivative of (2x-1/(x+1)) is 3/((x+1)^2)

What is the first derivative of (2x-1/(x+1)) ?

The first derivative of (2x-1/(x+1)) is 3/((x+1)^2)

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\frac{d}{d x} (\frac{2 x - 1}{x + 1})

\frac{3}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x - 1}{x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x - 1 ) ( x + 1 ) - \frac{d}{d x} ( x + 1 ) ( 2 x - 1 )}{( x + 1 ) ^{2}}

\frac{d}{d x} (2 x - 1) = 2

\frac{d}{d x} (x + 1) = 1

= \frac{2 ( x + 1 ) - 1 \cdot ( 2 x - 1 )}{( x + 1 ) ^{2}}

Simplify

\frac{2 ( x + 1 ) - 1 \cdot ( 2 x - 1 )}{( x + 1 ) ^{2}} : \frac{3}{( x + 1 ) ^{2}}

= \frac{3}{( x + 1 ) ^{2}}

x \to \infty lim (x^{7})

\int cos (30) d x

\int f (x) d x

y^{^{'}} = \frac{3 x sec ( \frac{y}{x} ) + y}{x}

f (x) = 1 - x

What is the derivative of (2x-1/(x+1)) ?
The derivative of (2x-1/(x+1)) is 3/((x+1)^2)
What is the first derivative of (2x-1/(x+1)) ?
The first derivative of (2x-1/(x+1)) is 3/((x+1)^2)