What is the derivative of f(x)=1-x ?

The derivative of f(x)=1-x is -1

What is the first derivative of f(x)=1-x ?

The first derivative of f(x)=1-x is -1

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derivative of

f (x) = 1 - x

- 1

Solution steps

\frac{d}{d x} (1 - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d x}{d x}

\frac{d}{d x} (1) = 0

\frac{d x}{d x} = 1

= 0 - 1

Simplify

= - 1

\frac{d}{d x} (\frac{x ^{2} - 2 x}{x + 1})

y^{^{'}} = - \frac{y}{x} + e^{x}

f (x) = sin (3 x) - cos (2 x)

\frac{\partial}{\partial x} (x^{3} + 4)

\int_{0}^{1} e^{- s t} t d t

What is the derivative of f(x)=1-x ?
The derivative of f(x)=1-x is -1
What is the first derivative of f(x)=1-x ?
The first derivative of f(x)=1-x is -1