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Popular >

y^'=-y/x+e^x

Solution

y^{^{'}} = - \frac{y}{x} + e^{x}

Solution

y = e^{x} - \frac{e ^{x}}{x} + \frac{c _{1}}{x}

Solution steps

y^{'} (x) = - \frac{y}{x} + e^{x}

Solve linear ODE:

y = e^{x} - \frac{e ^{x}}{x} + \frac{c _{1}}{x}

y = e^{x} - \frac{e ^{x}}{x} + \frac{c _{1}}{x}

Popular Examples

derivative of f(x)=sin(3x)-cos(2x)derivative of

f (x) = sin (3 x) - cos (2 x)

(\partial)/(\partial x)(x^3+4)

\frac{\partial}{\partial x} (x^{3} + 4)

integral from 0 to 1 of e^{-st}t

\int_{0}^{1} e^{- s t} t d t

y^{^{'}} = - 2 x tan (y)

slope of (5,-2),(7,10)slope

(5, - 2), (7, 10)

Frequently Asked Questions (FAQ)

What is the solution for y^'=-y/x+e^x ?
The solution for y^'=-y/x+e^x is y=e^x-(e^x)/x+(c_{1})/x