What is the solution for y^'=-2xtan(y) ?

The solution for y^'=-2xtan(y) is y=arcsin(e^{-x^2+c_{1}})+2pin,y=pi+arcsin(-e^{-x^2+c_{1}})+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=-2xtan(y)

y^{^{'}} = - 2 x tan (y)

y = arcsin (e^{- x^{2} + c_{1}}) + 2 πn, y = π + arcsin (- e^{- x^{2} + c_{1}}) + 2 πn

Solution steps

y^{'} (x) = - 2 x tan (y)

Solve separable ODE:

y = arcsin (e^{- x^{2} + c_{1}}) + 2 πn, y = π + arcsin (- e^{- x^{2} + c_{1}}) + 2 πn

y = arcsin (e^{- x^{2} + c_{1}}) + 2 πn, y = π + arcsin (- e^{- x^{2} + c_{1}}) + 2 πn

(5, - 2), (7, 10)

y = 3 x, x = 8 - y^{2}

\frac{d}{d x} (15)

\int (2 cos (x) - 3 sin (x) + x) d x

f (x) = (6 x + 7) (7 x - 8)

What is the solution for y^'=-2xtan(y) ?
The solution for y^'=-2xtan(y) is y=arcsin(e^{-x^2+c_{1}})+2pin,y=pi+arcsin(-e^{-x^2+c_{1}})+2pin