What is area y=4,2sqrt(x),((-3x+7))/2 ?

The answer to area y=4,2sqrt(x),((-3x+7))/2 is 4

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area y=4,2sqrt(x),((-3x+7))/2

area

y = 4, 2 x, \frac{( - 3 x + 7 )}{2}

4

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

4 = 2 x : x = 4

4 = \frac{( - 3 x + 7 )}{2} : x = - \frac{1}{3}

2 x = \frac{( - 3 x + 7 )}{2} : x = 1

= \int_{- \frac{1}{3}}^{1} ∣ f_{1} (x) - f_{3} (x) ∣ d x + \int_{1}^{4} ∣ f_{2} (x) - f_{1} (x) ∣ d x

= \int_{- \frac{1}{3}}^{1} 4 - \frac{( - 3 x + 7 )}{2} d x + \int_{1}^{4} 2 x - 4 d x

\int_{- \frac{1}{3}}^{1} 4 - \frac{( - 3 x + 7 )}{2} d x = \frac{4}{3}

\int_{1}^{4} 2 x - 4 d x = \frac{8}{3}

= \frac{4}{3} + \frac{8}{3}

Simplify

= 4

n = 1 \sum \infty (1 + \frac{k}{n})^{n}

x \to - 8 - lim (\frac{- 5 x + 2}{x + 8})

\int 3 x sin (3 x) d x

\int x x^{2} - 16 d x

\frac{d}{d x} (x^{3} - 10 x^{2} + 36 x)

What is area y=4,2sqrt(x),((-3x+7))/2 ?
The answer to area y=4,2sqrt(x),((-3x+7))/2 is 4