What is the integral of 3xsin(3x) ?

The integral of 3xsin(3x) is -xcos(3x)+1/3 sin(3x)+C

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integral of 3xsin(3x)

\int 3 x sin (3 x) d x

- x cos (3 x) + \frac{1}{3} sin (3 x) + C

Solution steps

\int 3 x sin (3 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int x sin (3 x) d x

Apply Integration By Parts

: - \frac{1}{3} x cos (3 x) - \int - \frac{1}{3} cos (3 x) d x

= 3 (- \frac{1}{3} x cos (3 x) - \int - \frac{1}{3} cos (3 x) d x)

\int - \frac{1}{3} cos (3 x) d x = - \frac{1}{9} sin (3 x)

= 3 (- \frac{1}{3} x cos (3 x) - (- \frac{1}{9} sin (3 x)))

Simplify

3 (- \frac{1}{3} x cos (3 x) - (- \frac{1}{9} sin (3 x))) : - x cos (3 x) + \frac{1}{3} sin (3 x)

= - x cos (3 x) + \frac{1}{3} sin (3 x)

Add a constant to the solution

= - x cos (3 x) + \frac{1}{3} sin (3 x) + C

\int x x^{2} - 16 d x

\frac{d}{d x} (x^{3} - 10 x^{2} + 36 x)

\int 9 x y d y

What is the integral of 3xsin(3x) ?
The integral of 3xsin(3x) is -xcos(3x)+1/3 sin(3x)+C