What is the derivative of x^3-10x^2+36x ?

The derivative of x^3-10x^2+36x is 3x^2-20x+36

What is the first derivative of x^3-10x^2+36x ?

The first derivative of x^3-10x^2+36x is 3x^2-20x+36

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\frac{d}{d x} (x^{3} - 10 x^{2} + 36 x)

3 x^{2} - 20 x + 36

Solution steps

\frac{d}{d x} (x^{3} - 10 x^{2} + 36 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (10 x^{2}) + \frac{d}{d x} (36 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (10 x^{2}) = 20 x

\frac{d}{d x} (36 x) = 36

= 3 x^{2} - 20 x + 36

\int 9 x y d y

x \to \infty lim (x - 4)

\frac{d}{d x} (- e^{c o s (x)} sin (x))

What is the derivative of x^3-10x^2+36x ?
The derivative of x^3-10x^2+36x is 3x^2-20x+36
What is the first derivative of x^3-10x^2+36x ?
The first derivative of x^3-10x^2+36x is 3x^2-20x+36