What is (\partial)/(\partial x)(cos(2x-y)) ?

The answer to (\partial)/(\partial x)(cos(2x-y)) is -sin(2x-y)*2

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(\partial)/(\partial x)(cos(2x-y))

\frac{\partial}{\partial x} (cos (2 x - y))

- sin (2 x - y) \cdot 2

Solution steps

\frac{\partial}{\partial x} (cos (2 x - y))

Treat

y

as a constant

Apply the chain rule:

- sin (2 x - y) \frac{\partial}{\partial x} (2 x - y)

= - sin (2 x - y) \frac{\partial}{\partial x} (2 x - y)

\frac{\partial}{\partial x} (2 x - y) = 2

= - sin (2 x - y) \cdot 2

\int x ln (x^{6}) d x

\frac{d}{d x} (4 x^{2} y)

x = - 5, x = 3, y = 10 x, y = x^{2} - 11

\frac{ln ( x )}{2} + 2

\frac{\partial}{\partial y} (1 + x ln (x y - 5))

What is (\partial)/(\partial x)(cos(2x-y)) ?
The answer to (\partial)/(\partial x)(cos(2x-y)) is -sin(2x-y)*2