What is the derivative of 4x^2y ?

The derivative of 4x^2y is 4(2xy+(dy)/(dx)x^2)

What is the first derivative of 4x^2y ?

The first derivative of 4x^2y is 4(2xy+(dy)/(dx)x^2)

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\frac{d}{d x} (4 x^{2} y)

4 (2 x y + \frac{d y}{d x} x^{2})

Solution steps

\frac{d}{d x} (4 x^{2} y)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{2} y)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = y

= 4 (\frac{d}{d x} (x^{2}) y + \frac{d y}{d x} x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= 4 (2 x y + \frac{d y}{d x} x^{2})

x = - 5, x = 3, y = 10 x, y = x^{2} - 11

\frac{ln ( x )}{2} + 2

\frac{\partial}{\partial y} (1 + x ln (x y - 5))

\frac{d}{d x} (7 sin (2 x))

\frac{d}{d x} ((2 x + 3)^{5})

What is the derivative of 4x^2y ?
The derivative of 4x^2y is 4(2xy+(dy)/(dx)x^2)
What is the first derivative of 4x^2y ?
The first derivative of 4x^2y is 4(2xy+(dy)/(dx)x^2)